Answer:
Step-by-step explanation:
Hello,
[tex]\dfrac{p}{q}*\dfrac{q}{p}=1=(2x+2)(2-x)\\\\<=> 4x-2x^2+4-2x=1\\\\<=> -2x^2+2x+4-1=0\\\\<=> -2x^2+2x+3=0\\\\[/tex]
There are two solutions
[tex]\Delta=b^2-4ac=2^2+4*2*3=4+24=28=7*4\\x_1=\dfrac{-2+\sqrt{7*4}}{-4}=\dfrac{-2+2\sqrt{7}}{-4}=\dfrac{1-\sqrt{7}}{2}\\x_2=\dfrac{1+\sqrt{7}}{2}\\[/tex]
Hope this helps
