AnnaDbar
AnnaDbar AnnaDbar
  • 23-07-2020
  • Mathematics
contestada

Find the x-value of the removable discontinuity of the function. ​

Find the xvalue of the removable discontinuity of the function class=

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xKelvin
xKelvin xKelvin
  • 23-07-2020

Answer:

x=2

Step-by-step explanation:

[tex]f(x)=\frac{x^2-4}{x^2-12x+20}[/tex]

Factor the numerator and denominator:

[tex]f(x)=\frac{(x-2)(x+2)}{(x-2)(x-10)}[/tex]

We can remove (x-2) from the function:

[tex]f(x)=\frac{x+2}{x-10}[/tex]

(x-2) is a removable discontinuity.

The x-value of x-2 is x=2.

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