angeldouglas006
angeldouglas006 angeldouglas006
  • 24-07-2020
  • Mathematics
contestada

help me please
really need it asap​

help me please really need it asap class=

Respuesta :

fricknjoronge
fricknjoronge fricknjoronge
  • 24-07-2020

Answer:

50

Step-by-step explanation:

Answer Link
sowjanyagudimetla6
sowjanyagudimetla6 sowjanyagudimetla6
  • 24-07-2020

Answer:

A) 2/3

B) 4 sqrt 30/9 = y

C) P= 3/4 * sqrt 2

Step-by-step explanation:

A.) A = K*B

1= K * 3

K = 1/3

Now we will find the unknown A value

A = 1/3 * 2

A= 2/3

B) x=k* y^2

27 = k * 4^2

K= 27/16

Now , we will find the unknown value of y

10= 27/16 * y^2

10*16/27 = y^2

Sqrt of 160/27 =y

4 sqrt 10/3 sqrt 3 =y

4 sqrt 30/9 = y

C) p = k * sqrt Q

3= k * sqrt 16

3 = k * 4

K= 3/4

Now, when we substitute the value of k in to the variation

P= 3/4 * sqrt 2

Answer Link

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