andyu391 andyu391

26-07-2020
Mathematics

contestada

If $y^2= 36$, what is the greatest possible value of $y^3$?

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sqdancefan sqdancefan

26-07-2020

Answer:

216

Step-by-step explanation:

y = ±√36 = ±6

y³ = (±6)³ = ±216

The largest of these values is 216, the greatest possible value of y.

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