Answer:
SMALLER INTEGER = 3
LARGER INTEGER = 5
Step-by-step explanation:
Given the following :
Five times the larger of two consecutive odd integers is equal to one more than eight times the smaller
Let the larger = L, smaller = L - 2
5 × L = 8(L - 2) + 1
5L= 8L - 16 + 1
5L = 8L - 15
5L - 8L = - 15
-3L = - 15
Divide both sides by 3
L = 5
The smaller integer will be (L - 2)
(L - 2) = (5 - 2) = 3
HENCE, SMALLER INTEGER = 3
LARGER INTEGER = 5
