LILY3214 LILY3214
  • 21-09-2016
  • Mathematics
contestada

10x-35+3ax=5ax-7a solve for "a" for which the equation is an identity.

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asoumah23
asoumah23 asoumah23
  • 21-09-2016
10x - 35 +3ax=5ax-7a
10x-35=5ax-3ax-7a
10x-35=a(2x-7)===>  a= (2x-7)/(10x-35)
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dasetka
dasetka dasetka
  • 21-09-2016
10x - 35 + 3ax = 5ax - 7a   Subtract 3ax from both sides
10x - 35 = 2ax - 7a   Factor a out of the right side
10x - 35 = a (2x - 7)   Divide both sides by (2x - 7)
[tex] \frac{10x - 35}{2x - 7} [/tex] = a  Switch the sides to make it easier to read
a = [tex] \frac{10x - 35}{2x - 7} [/tex] 
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