Answer:
Explanation:
CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O
100 gm + 2000 mL of M HCl
Amount of HCl remaining = .1018 M of 16.62 mL
= .1018 x 16.62 mL of M HCl
= 1.69 mL of M HCl
Initial HCl taken = 50 mL of .1035 M HCl
= 5.175 mL of M HCl
HCl reacted = 5.175 - 1.69 mL of M HCl
= 3.485 mL of M HCl
2000 mL of M HCl reacts with 100 gm of CaCO₃
3.485 mL of M HCl will react with .174 grams of CaCO₃
percentage of calcium carbonate = .174 x 100 / .2027
= 85.84 %
