Answer:
First find the cubes and squares of the 1st and 2nd expression.
1st expression ⇒ [tex](-\frac{2}{3} x^2y)^3 = -\frac{8}{27}x^6y^3[/tex]
2nd expression ⇒ [tex](-\frac{3}{4}xy^2)^2 = -\frac{9}{16}xy^4[/tex]
Now you all you need to do is multiply the 1st expression to 2nd expression.
[tex]-\frac{8}{27}x^6y^3*-\frac{9}{16}xy^4\\\\= \frac{72}{432} x^7y^7[/tex]
