jessiebealynn5141 jessiebealynn5141
  • 22-10-2020
  • Chemistry
contestada

At constant temperature, He effuses 6.04 times faster than a gas having an unknown molar mass. Determine the molar mass of the unknown gas.

Respuesta :

Xema8 Xema8
  • 25-10-2020

Answer:

Explanation:

Rate of effusion =

[tex]Rate of effusion = \frac{k}{\sqrt{M} }[/tex]

k is a constant and M is molecular mass .

Molecular mass of He = 4 .

rate of effusion of He = r₁

Molecular mass of unknown compound = M

rate of effusion of unknown gas  = r₂

r₁ = k / √4

r₂ = k / √M

r₁ / r₂ = √ ( M/4 )

6.04 = √ ( M/4 )

36.48 = M/4

M = 146 approx .

molecular mass of unknown gas = 146 .

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