23-10-2020
Mathematics

contestada

Evaluate 8x−y2−3 when x=−1/4 and y=3.

Respuesta :

altavistard altavistard

23-10-2020

Answer:

-14

Step-by-step explanation:

I believe you meant 8x−y^2−3. The expression 8x−y2−3 is meaningless.

Letting x take on the vaue -1/4 and y the value 3, we get:

8(-1/4) − (3)^2−3, or

-2 - 9 - 3, or

-2 - 12. Final answer is -14

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