joedellfrederck
joedellfrederck joedellfrederck
  • 22-11-2020
  • Mathematics
contestada


Can somebody help me

Can somebody help me class=

Respuesta :

10betsi10 10betsi10
  • 22-11-2020
The answer to this is B
Answer Link
xenia168
xenia168 xenia168
  • 23-11-2020

Answer:

 (B)

Step-by-step explanation:

LCM(15, 20) = 60

[tex]\frac{9}{15}[/tex] and [tex]\frac{14}{20}[/tex]

[tex]\frac{3}{5}[/tex] and [tex]\frac{7}{10}[/tex]

[tex]\frac{6}{10}[/tex] < [tex]\frac{7}{10}[/tex]

(B)

Answer Link

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