kayiokloso kayiokloso
  • 23-11-2020
  • Mathematics
contestada


[tex] \sqrt{ \sqrt{?} 27a} [/tex]
27a​

Respuesta :

braedintabler braedintabler
  • 23-11-2020

Answer:

[tex]\sqrt{\sqrt{27a}} \\\\=\sqrt{\sqrt{3^3a}} \\\\=\sqrt{3\sqrt{3a}} \\\\or\\\\=(3(3a)^{1/2})^{1/2}=3^{1/2}(3a)^{1/4}[/tex]

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