Answer:
AC is approximately 0.3178
Step-by-step explanation:
The given parameters are;
In ΔPAB
CD ║ EF ║ AB
The area of triangle ΔPEF = 1/3 × area of triangle ΔPAB
Therefore, PE = 1/√3·PA
PA = √3
We have area of ΔPCD = 2/3 × area of triangle ΔPAB
∴ PC = √(2/3) × PA = √(2/3) × √3
PC = √2
Therefore, AC = PA - PC = √3 - √2
AC = √3 - √2 ≈ 0.3178
