Hello!
[tex]\large\boxed{x^{4}}[/tex]
Recall that:
[tex]\sqrt[z]{x^{y} }[/tex] is equal to [tex]x^{\frac{y}{z} }[/tex]. Therefore:
[tex]\sqrt[3]{x^{2} } = x^{\frac{2}{3} }[/tex]
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:
[tex](x^{\frac{2}{3} })^{6} = x^{\frac{2}{3}* 6 } = x^{\frac{12}{3} } = x^{4}[/tex]
