Answer:
0.985
Explanation:
A system contains three components that are arranged in parallel, they include 0.9, 0.7 and 0.5
Therefore the system reliability can be calculated as follows
= 1 - (1 -0.9)×(1-0.7)×(1-0.5)
= 1 - 0.1×0.3×0.5
= 1 - 0.1×0.15
= 1 -0.015
= 0.985
Hencd the system reliability is 0.985
