Answer:
One answer is (x, y) = (1, 0).
See below.
Step-by-step explanation:
If (x,y) is on the x axis then y = 0.
When y = 0.
x^4 - 15x^2 + 14 = 0
Let x^2 = z, then:
z^2 - 15z + 14 = 0
(z - 1)(z - 14) = 0
So z = 1, 14.
But z = x^2,
so x could be +/- 1 or +/-√14
and (x, y) could be (1, 0), (-1, 0), (√14, 0) and (-√14, 0).
These are the zeroes of the function.
