northdylann
northdylann northdylann
  • 24-12-2020
  • Chemistry
contestada

Calculate the [H3O+] of 0.10 M HNO2 at equilibrium. Given: Ka = 4.46 × 10-4.

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Stephen46
Stephen46 Stephen46
  • 24-12-2020

Answer:

0.0067 mol/dm³

Explanation:

The [H3O+] of HNO2 can be found by using the formula

[tex][H_3O^{ + } ] = \sqrt{Kac} [/tex]

Ka is the acid dissociation constant

c is the concentration of the acid

From the question we have

[tex][H3O^{ + } ] = \sqrt{4.46 \times {10}^{ - 4} \times 0.1} \\ = 0.006678...[/tex]

We have the final answer as

0.0067 mol/dm³

Hope this helps you

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