monalisannorom monalisannorom
  • 24-01-2021
  • Chemistry
contestada

1. Calculate the percent composition for each element in CH 206 Glucose.

Respuesta :

ardni313
ardni313 ardni313
  • 27-01-2021

%C = 40

%H = 6.67

%O = 53.33

Further explanation

Given

Glucose  C₆H₁₂O₆

Required

The percent composition

Solution

MW Gulucose = 180 g/mol

Ar C = 12 g/mol

Ar H = 1 g/mol

Ar O = 16 g/mol

%C = 6.12/180 x 100% = 40%

%H = 12.1/180 x 100% = 6.67%

%O = 6.16/180 x 100% = 53.33%

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