Answer:
No solutions
Step-by-step explanation:
2x^2 + 5x + 4 = 0 ---> a = 2, b = 5, c = 4
[tex]x = \frac{-b +- \sqrt{b^{2} -4ac} }{2a}[/tex]
[tex]x = \frac{-5 +- \sqrt{5^{2} - 4(2)(4)}} {2(2)}[/tex]
[tex]x = \frac{-5 +- \sqrt{25 - 32} }{4}[/tex]
[tex]x = \frac{-5+-\sqrt{-7}}{4}[/tex]
Since the number inside the square root is negative, the answer will be no solutions.
Hope this helps!
