Answer:
Equation of the straight line in point-slope form
y -(-7) = [tex]\frac{-3}{4}[/tex](x-8)
Equation of the straight line
3x +4y +4=0
Step-by-step explanation:
Explanation:-
Given that the point ( 8,-7) and [tex]m = \frac{-3}{4}[/tex]
Equation of the straight line passing through the point (x₁, y₁) and having slope 'm'
y - y₁ = m (x-x₁)
y -(-7) = [tex]\frac{-3}{4}[/tex](x-8)
4( y+7) = -3(x-8)
4y +28 = -3x +24
3x +4y +28 -24 =0
3x +4y +4=0
