Given:
The equation is
[tex]P=-3-4L-6[/tex]
To find:
The formula for L.
Solution:
We have,
[tex]P=-3-4L-6[/tex]
It can be written as
[tex]P=(-3-6)-4L[/tex]
[tex]P=-9-4L[/tex]
We need to isolate variable L.
Adding 6 on both sides, we get
[tex]P+6=-4L[/tex]
Dividing both sides by -4, we get
[tex]\dfrac{P+6}{-4}=L[/tex]
[tex]\dfrac{P}{-4}+\dfrac{6}{-4}=L[/tex]
[tex]-\dfrac{P}{4}-1.5=L[/tex]
Therefore, the required value of L in terms of P is [tex]L=-\dfrac{P}{4}-1.5[/tex].
