Answer:
[tex]\sum (r+1)^2 = 90[/tex]
Step-by-step explanation:
Given
[tex]\sum (r+1)^2; r = 1,2....5[/tex]
Required
Evaluate
[tex]\sum (r+1)^2; r = 1,2....5[/tex] is equivalent to :
[tex](1 + 1)^2 +(2 + 1)^2 +(3 + 1)^2 +(4 + 1)^2 +(5 + 1)^2[/tex]
[tex](2)^2 +(3)^2 +(4)^2 +(5)^2 +(6)^2[/tex]
[tex]4 + 9 + 16 + 25 + 36[/tex]
[tex]90[/tex]
Hence:
[tex]\sum (r+1)^2 = 90[/tex]
