ari925585 ari925585
  • 22-03-2021
  • Mathematics
contestada

Can someone please help me g(x) = 17 -*; g(6)

Respuesta :

jhonpiad
jhonpiad jhonpiad
  • 22-03-2021

Answer:

(x + 6)(x-4) = -16

x² + 2x -24 = -16

x² + 2x - 8 = 0

(x + 4)(x-2) = 0

x = - 4 or x = 2

Step-by-step explanation:

Answer Link
ngoa1575 ngoa1575
  • 22-03-2021

Answer:

Divide each term in G(6)=17−(2/3)x by 6.

G(6)/6=17/6−(2/3)x⋅16

Cancel the common factor of 6.

G=17/6−(2/3)x⋅16

Simplify each term.

G=17/6−x/9

Step-by-step explanation:

Answer Link

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