dreamboatbabyy dreamboatbabyy

23-03-2021
Mathematics

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2cos2x + 1÷2sin2x = sin^2x
[tex]2 \cos(2x) + \frac{1}{2} \sin(2x) = { \sin(x) }^{2} [/tex]

Respuesta :

jonahgooden jonahgooden

23-03-2021

Answer:

3sin(x)−cos(2x)+1

cos(3x)

cos(2x)

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