ABCD is a rectangle. if AC = 3y/5 anf BD= 3(y-4), find the length of each diagonal

a.) 4; LN = MP = 4
b.) 3; LN = MP = 7
c.) 1; LN = MP = 67
d.) 5/3; LN = MP = 29/3

Question

yu4kikieT7immymcroxa yu4kikieT7immymcroxa

23-11-2016
Mathematics

contestada

ABCD is a rectangle. if AC = 3y/5 anf BD= 3(y-4), find the length of each diagonal

a.) 4; LN = MP = 4
b.) 3; LN = MP = 7
c.) 1; LN = MP = 67
d.) 5/3; LN = MP = 29/3

Respuesta :

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pkmnmushy pkmnmushy · Answer 1 · 2016-12-07T01:22:59+01:00

pkmnmushy pkmnmushy

07-12-2016

Remember please that Diagonals of a Rectangle are equal to each other: 3y/5 = 3(y-4)
So
3y = 15(y-4)
3y = 15y - 60
60 = 12y
y = 5 Diagonals are both 3 units
With that you will be able to know which is the answer from your options

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ABCD is a rectangle. if AC = 3y/5 anf BD= 3(y-4), find the length of each diagonal a.) 4; LN = MP = 4 b.) 3; LN = MP = 7 c.) 1; LN = MP = 67 d.) 5/3; LN = MP = 29/3

Respuesta :

Otras preguntas

ABCD is a rectangle. if AC = 3y/5 anf BD= 3(y-4), find the length of each diagonal

a.) 4; LN = MP = 4
b.) 3; LN = MP = 7
c.) 1; LN = MP = 67
d.) 5/3; LN = MP = 29/3