cr3dianlam0pso cr3dianlam0pso

24-11-2016
Mathematics

contestada

Find the axis of symmetry of the graph of the function.

f(x) = 2x2 - 16x + 27

A. x = -3

B. x = 4

C. x = -5

D. x = 6

Respuesta :

apologiabiology apologiabiology

24-11-2016

for f(x)=ax^2+bx+c
the axis of symmetry is -b/2a

f(x)=2x^2-16x+27
a=2
b=-16
-b/2a=-(-16)/2(2)=16/4=4
x=4

B is answer

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syed514 syed514

27-11-2016

x will be equal to 4. So, the right answer is B.

Answer Link

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