Answer:
286 K
Explanation:
From the question,
Applying Charles law,
V/T = V'/T'.................... Equation 1
Where V = Initial Volume of gas, T = Initial Temperature of gas in Kelvin, V' = Final Volume of gas, T' = Final Temperature of gas in Kelvin
Make T' the subject of the equation
T' = V'T/V.................. Equation 2
Given: V = 10.0 L, V' = 20.0 L, T = 20°C = (20+273) = 293 K.
Substitute these values into equation 2
T' = (20×293)/10
T' = 586 K
Hence the temperature of the gas is 586 K
