Answer:
Step-by-step explanation:
[tex]\sqrt{x-3}[/tex] = x - 5 ( x ≥ 3 )
( [tex]\sqrt{x-3}[/tex] )² = ( x - 5 )²
x - 3 = x² - 10x + 25
x² - 11x + 28 = 0
(x - 4)(x - 7) = 0
[tex]x_{1}[/tex] = 7
[tex]x_{2}[/tex] = 4
Check the answer:
1). x = 7
[tex]\sqrt{7-3}[/tex] = 7 - 2
√4 = 2
2 = 2
2). x = 4
[tex]\sqrt{4-3}[/tex] = 4 - 5
1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.
