kuldeepsinghmaheshi kuldeepsinghmaheshi
  • 25-04-2021
  • Mathematics
contestada

x = 1 + root 2 , find the value of (x - 1/x )^3​

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 30-04-2021

Answer:

[tex](\sqrt{2})^3[/tex]

Step-by-step explanation:

Given the expression

[tex](x - \frac{1}{x} )^3[/tex]

Simplify

[tex](\frac{x^2-x}{x} )^3[/tex]

Given that x = 1+√2

Substitute

[tex](\frac{(1+\sqrt{2} )^2-(1+\sqrt{2} )}{1+\sqrt{2} } )^3\\=( \frac{1+2\sqrt{2} +2 - 1 - \sqrt{2}}{1+\sqrt{2}} )^3\\= (\frac{\sqrt{2}+2}{1+\sqrt{2}})^3 \\Rationalize\\= (\frac{\sqrt{2}-2+2-2\sqrt{2}}{1-2})^3 \\=( \frac{-\sqrt{2}}{-1})^3 \\= (\sqrt{2})^3\\ \\[/tex]

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