oimomo
oimomo oimomo
  • 21-05-2021
  • Chemistry
contestada

How many grams would be in 4.45 x 10^23 molecules of N203

Respuesta :

samueladesida43
samueladesida43 samueladesida43
  • 26-05-2021

Answer:

56.24g

Explanation:

To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).

number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23

n = 4.45/6.02 × 10^(23 - 23)

n = 0.74 × 10^0

n = 0.74moles.

Using the formula below to find the mass of N2O3;

mole = mass ÷ molar mass

Molar mass of N2O3 = 14(2) + 16(3)

= 28 + 48

= 76g/mol

mass = mole × molar mass

Mass = 0.74 × 76

Mass = 56.24g

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