Answer:
Q = 797.5 cal
Explanation:
Given that,
Mass of iron, m = 50 g
The temperature rises from 55°C to 200°C.
We need to find the heat needed to raise the temperature. The heat raised is given by :
[tex]Q=mc\Delta T[/tex]
Put all the values,
[tex]Q=50\times 0.11\times (200-55)\\\\Q=797.5\ cal[/tex]
So, 797.5 calories of heat is needed.
