Answer:
x = 5, x = -5
Step-by-step explanation:
First, you can notice both terms of the equation are divisible by 2, so you can factor it out to get:
2(x^2 - 25) = 0
You can recognize the expression x^2 - 25 as the special product for the difference of squares, so it would be factored into (x + 5)(x - 5). When we plug it in we get:
2(x + 5)(x - 5) = 0
Now, we can use the zero-product property to get two equations:
x + 5 = 0
-and-
x - 5 = 0
Solving them both we get:
x = 5, x = -5
