Respuesta :

prashant12345

Step-by-step explanation:

Centre of circle(h,k)=(1,-4)

radius of the circle(r)=2

Equation of the circle is,

(x-h)^2+(y-k)^2=r^2

(x-1)^2+(y+4)^2=2^2

x^2-2x+1+y^2+8y+16=4

x^2+y^2-2x+8y+13=0 is the req.equation of the circle.

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