Answer:
CH3COONa : CH3COOH = 1.74 : 1 (required to prepare a buffer at PH = 5)
Explanation:
Given that :
PH = 5
Calculate proportions of ethanoic acid and Sodium ethanoate to prepare Buffer solution
solution :
PH = Pka + Log ( CH3COONa / CH3COOH )
5.0 = 4.76 + Log ( CH3COONa / CH3COOH )
∴ Log ( CH3COONa / CH3COOH ) = 0.24
( CH3COONa / CH3COOH ) = 1.74
Therefore : CH3COONa : CH3COOH
1.74 : 1
