Respuesta :

sqdancefan

9514 1404 393

Answer:

  40

Step-by-step explanation:

The "initial value" is the value when x=0.

  [tex]f(x)=\dfrac{800}{1+19e^{-0.402x}}\\\\f(0) =\dfrac{800}{1+19e^0}=\dfrac{800}{1+19}=\dfrac{800}{20}\\\\=\boxed{40}[/tex]

The initial value is 40.