Respuesta :

ms7006747

Step-by-step explanation:

are (x1,y1) and (x2,y2) is

d=(y2−y1)+(x2−x1)2

Let (3,−1)=(x1,y1) and (6, 5) = =(x2,y2)

∴ d = (y2−y1)+(x2−x1)2

= (6)2+(3)2=36+9

= 45=9×5=35

So length of the line segment whose end

point are (3, -1) and (6, 5) is 35

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