Step-by-step explanation:
Given equation is 4/(s-3) + (s/2) = -2
=> [(4×2)+s(s-3)]/2(s-3) = -2
=> (8+s²-3s)/(2s-6) = -2
=> 8+s²-3s = -2(2s-6)
=> 8+s²-3s = -4s+12
=> s²-3s+8+4s-12 = 0
=> s²+s-4 = 0
The standard form is s²+s-4 = 0
