[tex]\displaystyle \large \boldsymbol{} (7 \sqrt[5]{6x-10}) ^2 +\backslash\!\!\!8=\frac{49}{x^{-\tfrac{2}{5} }} +\backslash\!\!\!8 \\\\\\ 49\!\!\!\! \diagup \sqrt[5]{(6x-10)^2} = 49\!\!\!\! \diagup \cdot \sqrt[5]{x^2} \ \ ; \\\\\\ (6x-10)^2=x^2 \\\\ (6x-x-10)(6x+x-10) =0 \Rightarrow x_1=2 \ ; \ x_2=\frac{10}{7 }[/tex]
