ejnedeufeuiwn1580 ejnedeufeuiwn1580
  • 22-11-2021
  • Mathematics
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Two consecutive numbers exist such that the sum of three times the first number and two less than the second number is equal to 411. What are those numbers?

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Аноним Аноним
  • 22-11-2021

Answer:

103 and 104

Step-by-step explanation:

Two consecutive numbers

x and x + 1

3 times the first number and 2 less than the second number = 411

               3x                       +                 (x + 1) - 2                         = 411

3x + (x + 1) - 2 = 411

combine like terms

4x - 1 = 411

4x = 412

dividde both sides by 4

x = 103

x + 1 = 104

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