umanaisabel07 umanaisabel07
  • 22-12-2021
  • Physics
contestada

9) when the distance was one fourth as much, what happened to the force between the objects?

in this case (G=6.67E-11)

Respuesta :

leena
leena leena
  • 23-12-2021

Hi there!

Recall Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = \frac{Gm_1m_2}{r^2}}[/tex]

G = Gravitational Constant

m1, m2 = mass of objects (kg)

r = distance between objects (m)

There is an INVERSE-SQUARE relationship between the gravitational force and the distance between the objects, so:

[tex]F_g = \frac{Gm_1m_2}{(\frac{1}{4}r)^2} = F_g = \frac{Gm_1m_2}{\frac{1}{16}r^2}[/tex]

[tex]= 16G\frac{m_1m_2}{r^2} = 16F_g[/tex]

Thus, the gravitational force between the objects would INCREASE by a factor of 16.

Answer Link

Otras preguntas

The terms are 4/10, n/30. The net price is $919.60. What is the cash price using the complement method? '
what is -5/12 * 8/13 in simplest form
Paul is 17. What is his approximate maximum heart rate?
In a low-income household in the developed world, more than 30% of a woman’s income typically goes toward __________. A. transportation costs B. child care C. c
The definition for Sponsors ASAP
A circular balloon has a diameter of 18 inches. What is the volume?
Emily’s neighbor Julia is helping her in the kitchen. Julia slices potatoes while Emily crushes the garlic. How would Emily communicate this to her grandmother?
For every 6 green apples in an orchard there where 9 red apples what is the ratio of green apples to red apples
Please help and explain!
Can someone help with this question i need it done asap!! will give you all my points and brainliest.