jonathanjm121004 jonathanjm121004
  • 24-02-2022
  • Chemistry
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How many moles are occupied by 2.2x10^23 particles of copper?

Respuesta :

jcherry99
jcherry99 jcherry99
  • 24-02-2022

Answer:

Explanation:

1mole of copper = 6.02 * 10^23 particles of copper

x mol of copper =2.2 * 10^23 particles

This is a proportion. All you need do is solve using the rules of proportions.

1/x = 6.02 * 10^23/2.2 * 10^23       Cross multiply

6.02 * 10^23x = 1* 2.2*10^23         Divide by 6.02 * 10^23

x = 2.2*10^23 / 6.02* 10^23

x = .365 mols of copper

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