just sub in ANY number for x and solve for y
5x + 7y = 19.....lets say x = 0
5(0) + 7y = 19
7y = 19
y = 19/7...so when x = 0, y = 19/7.....(0,19/7)
5x + 7y = 19....lets say x = 1
5(1) + 7y = 19
5 + 7y = 19
7y = 19 - 5
7y = 14
y = 14/7
y = 2.....so when x = 1, y = 2......(1,2)
5x + 7y = 19.....lets say x = 3
5(3) + 7y = 19
15 + 7y = 19
7y = 19 - 15
7y = 4
y = 4/7...so when x = 3, y = 4/7.....(3,4/7)
