AcaciaBlossom
AcaciaBlossom AcaciaBlossom
  • 26-01-2017
  • Physics
contestada

The velocity of an object increases from -10 m/s to -15 m/s in 2.0 s. What is the average acceleration of the object?

Respuesta :

TheHero
TheHero TheHero
  • 26-01-2017
Average acceleration is given by:

a_average = V2 - V1/dt   = -15 +10/2 = -2.5 m/s^2
Answer Link
aachen
aachen aachen
  • 15-10-2019

Answer:

[tex]a=-2.5 \ m/s^2.[/tex]

Explanation:

It is given that.

Initial velocity, [tex]v_i=-10\ m/s[/tex].

Final velocity, [tex]v_f=-15 \ m/s[/tex].

Also, time taken during the process, [tex]t=2.0 \ s[/tex].

So, average acceleration, a is given by:

[tex]a=\dfrac{v_f-v_i}{t}[/tex]

Putting all the given values in above equation.

[tex]a=\dfrac{-15-(-10)}{2} \ m/s^2=-2.5 \ m/s^2.[/tex]

Hence, it is the required solution.

Answer Link

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