Answer:
6.6 L ( if you wrote your Q correctly)
Explanation:
2 Al + 1 N2 = 2 Al N
Al mole weight = 26.981 gm
given 15.9 Al How many L of N2 are needed?
15.9 / 26.981 = .5893 moles of Al
we need 1/2 as many moles of N2 ( from the balanced equation above)
= .29465 moles of N2
22.4 L/ mole for STP gas = 6.6 L
