Answer:
Step-by-step explanation:
(x+y)/2 - (x-y)/6 = 16
x/3 + (x+2y)/3 = 14
Multiply first equation by 6
3(x+y) - (x - y) = 96
2x + 4y = 96
x + 2y = 48 (A)
Multiply second equation by 3
x + x + 2y = 42
x + y = 21 (B)
Subtract A - B:-
y = 27
So:
x + 27 = 21
x = -6.
The quadratic relation
is f(x) = a(x - 27)(x + 6)
= a(x^2 - 21x - 162) where a is some constant
Vertex form:
f(x) = a[(x - 10.5)^2 - 110.25 - 162]
f(x) = a[(x - 10.5)^2 - 272.25]
f(x) = a[(x - 10.5)^2 - 272.25a.
