[tex]\sf\huge \green{\underbrace{\red{Answer}}}:[/tex]
y = 4
Correct option is (C)
Step-by-step explanation:
-2x - 5y = -2 {taking minus(-) common}
⠀
2x + 5y = 2 [equation 1]
⠀
3x + 6y = -3 {taking 3 common}
⠀
x + 2y = -1 [equation 2]
⠀
{taking 2y of equation 2 on RHS}
⠀
x = -1 - 2y [equation 3]
⠀
{substituting of equation 3 in equation 1}
⠀
2(-1 - 2y) + 5y = 2
- 2 - 4y + 5y = 2
y - 2 = 2
y = 2 + 2
⠀
y = 4
