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Consider the graph of the function f(x)=2^x.

Match each transformation of function f to a feature of the transformed function.
y-intercept at (0,4)
y-intercept at (0,2)
function decreases as x increases
asymptote of y=2

m(x)=-f(x)
g(x)=2f(x)
j(x)=f(x+2)
h(x)=f(x)+2

Consider the graph of the function fx2x Match each transformation of function f to a feature of the transformed function yintercept at 04 yintercept at 02 funct class=

Respuesta :

Answer:

Step-by-step explanation:

1 -     f(x) = f (x + 2) = 2^x+2

      { when x = 0, y = 2² = 4 }

     so the function { y - intercept at (0, 4) }

2 -   m(x) = -f(x) = - 2^x

      2^x increases as x increases

     So -2^x {decreases as x increases}

3 -  g(x) = 2f(x) = 2, 2^x = 2^x+1

    { when x = 0, y = 2^1 = 2 }

   So the function { y-intercept at (0, 2)

4 - h(x) = f(x)+ 2 = 2^x + 2

f(x)'s asymptote of y = 0

so {f(x) + 2}'s asymptote of y =2

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