Respuesta :

KarkiDikshya01

Answer:

The blank expression must be

[tex] {3}^{2} [/tex]

because

[tex] {v}^{2} - 6v + blank \\ = {v}^{2} - 2 \times v \times 3 + { 3}^{2} \\ = {(v - 3)}^{2} [/tex]

hope this helps:)

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