brooklynoseni2008 brooklynoseni2008
  • 27-05-2022
  • Mathematics
contestada

What are the roots of the equation x² + 6x-9 = 07

Respuesta :

yagami094845 yagami094845
  • 27-05-2022

Answer:

x1 =-3+3[tex]\sqrt{2}[/tex] and x2=-3-3[tex]\sqrt{2\\}[/tex]

Step-by-step explanation:

x² + 6x-9 = 0

-6±[tex]\sqrt{6^{2}-4(1)(-9) }[/tex] / 2

-6±[tex]\sqrt{72}[/tex] /2

so

x1 = -6+[tex]\sqrt{72[/tex] /2

x1 =-3+3[tex]\sqrt{2}[/tex]

and

x2 = -6-[tex]\sqrt{72[/tex] /2

x2=-3-3    [tex]\sqrt{2\\}[/tex]

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