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A car is being tested on a track. The driver approaches the test section at a speed of 28 m s−1. He then accelerates at a uniform rate between two markers separated by 100 m. The car reaches a speed of 41 m s−1.

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The uniform acceleration of the car is 4.485 m/s².

Acceleration of the car

The uniform acceleration of the car is calculated as follows;

v² = u² + 2as

a = (v² - u²)/2s

where;

  • v is final velocity = 41 m/s
  • u is initial velocity = 28 m/s
  • s is distance = 100 m
  • a is acceleration = ?

a = (41² - 28²)/(2 x 100)

a = 4.485 m/s²

Thus, the uniform acceleration of the car is 4.485 m/s².

Learn more about uniform acceleration here: https://brainly.com/question/2505743

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